In the same way that we think of real numbers as being points on a line,
it is natural to identify a complex number *z*=*a*+*ib* with the point
(*a*,*b*)
in the cartesian plane. Expressions such as ``the complex number
*z*'',
and ``the point *z*'' are now interchangeable.

We consider the a real number *x* to be the
complex
number *x*+ 0*i* and in this way we can think of the real numbers as a
subset of the complex numbers. The reals are just the
x-axis in the complex plane.

The modulus of the complex number *z*= *a* + *ib* now can be interpreted
as the distance from *z* to the origin in the complex plane.

Since the hypotenuse of a right triangle is longer than the other sides, we have

for every complex number *z*.

We can also think of the point *z*= *a*+ *ib* as the vector (*a*,*b*). From
this point of view, the addition of complex numbers is equivalent to
vector addition in two dimensions and we can visualize it as laying
arrows tail to end. (Picture)

We see in this way that the distance between two
points
*z* and *w* in the complex plane is |*z*-*w*|.

Exercise: Prove this last statement algebraically. (Proof.)

Exercise: Prove the ``Parallellogram law''

The ``Triangle'' inequality

is easily seen to hold.

(Proof.)

Exercise: Prove the Triangle inequality for *n* complex numbers

Here are some more exercises.

Exercise 1

Exercise 2

Exercise 3

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