These are integrals of the following form:
We have two cases: both m and n are even or at least one of them is
Suppose n is odd. Hence n = 2k + 1. So hold. Therefore, we have
which suggests the substitution . Indeed, we have and hence
The latest integral is a polynomial function of u which is easy to
Remark. Note that if m is odd, then we
will split and carry the same calculations. In this case,
the substitution will be .
The main idea behind is to use the trigonometric identities
Remark. The following two formulas may be helpful in integrating powers of sine and cosine.
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Author: Mohamed Amine Khamsi