mathematic wrote:
Shadow wrote:
mathematic wrote:
Shadow wrote:
Oh? What if there are negative terms? Or worse, a zero term?
a-b>0 is definition for a>b and is usually the most generally direct way to do things. In this particular case the alternative can work with the right caveats, but without them things are incomplete.
My comment was a reference to the specific problem, not as a general approach.
Naturally, but that's no reason not to be careful. Remember, the original poster cannot read your mind, and just because you have checked the requirements to use the method you describe in your head, doesn't mean the op has, and if not advice like that can do more harm than good.
I don't understand why you are making such a big deal. The original question was for a specific problem and my response was to that specific problem. I see no reason why the proposer would think I was trying to give an answer for all series.
But your original "Easy Answer" was technically incorrect. If someone took your solution verbatim and wrote:
mathematic wrote:
Take the reciprocal and show that it is an increasing sequence.
(n + 1/n) < (n+1 + 1/(n+1))
then there would be a good chance that the OP would lose a significant number of points on that problem. The reason is because this is not a mathematically sound proof, as pointed out by
Shadow in the first line of this quote:
Shadow wrote:
Oh? What if there are negative terms? Or worse, a zero term?
a-b>0 is definition for a>b and is usually the most generally direct way to do things. In this particular case the alternative can work with the right caveats, but without them things are incomplete.
However, I would like to point out that although you have to check that everything is positive (which is very trivial),
mathematic's trick is quicker and it simplifies a lot of the messy algebra. So, in my opinion, going the alternative route in this case is preferable.~