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 Post subject: Series
PostPosted: Mon, 9 Jul 2012 04:50:06 UTC 
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How to find series representation for quantities such as \pi e, \frac{\pi }{e}, {\pi ^\pi }, and {e^e}?


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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 04:53:49 UTC 
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glebovg wrote:
How to find series representation for quantities such as \pi e, \frac{\pi }{e}, {\pi ^\pi }, and {e^e}?


e^e=\sum{e^n\over n!}

\pi^\pi=\sum {(\pi\log\pi)^n\over n!}

For \pi e use the Cauchy rule for multiplication of power series and pick your favorites for \pi and e

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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 05:02:12 UTC 
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Shadow wrote:
glebovg wrote:
How to find series representation for quantities such as \pi e, \frac{\pi }{e}, {\pi ^\pi }, and {e^e}?


e^e=\sum{e^n\over n!}

\pi^\pi=\sum {(\pi\log\pi)^n\over n!}

For \pi e use the Cauchy rule for multiplication of power series and pick your favorites for \pi and e


How did you come up with {\pi ^\pi }?


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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 05:16:02 UTC 
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glebovg wrote:
Shadow wrote:
glebovg wrote:
How to find series representation for quantities such as \pi e, \frac{\pi }{e}, {\pi ^\pi }, and {e^e}?


e^e=\sum{e^n\over n!}

\pi^\pi=\sum {(\pi\log\pi)^n\over n!}

For \pi e use the Cauchy rule for multiplication of power series and pick your favorites for \pi and e


How did you come up with {\pi ^\pi }?


Just modified the basic e^x by recalling \pi=e^{\log\pi}, a simple parlor trick.

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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 05:23:52 UTC 
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Also, I do not think the Cauchy product would give me the explicit form for \pi e and \frac{\pi }{e}.


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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 05:33:36 UTC 
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glebovg wrote:
Also, I do not think the Cauchy product would give me the explicit form for \pi e and \frac{\pi }{e}.


Very well, here are some other versions:

\pi e=\sum{(1+\log\pi)^n\over n!}

{\pi\over e}=\sum{(\log\pi -1)^n\over n!}

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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 05:43:13 UTC 
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How do you generally come up with series representations, say for \pi?

I know Ramanujan came up with a lot of formulas for \pi and other quantities without any derivations, but how would you derive series for quantities such as \pi?


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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 05:50:45 UTC 
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glebovg wrote:
How do you generally come up with series representations, say for \pi?

I know Ramanujan came up with a lot of formulas for \pi and other quantities without any derivations, but how would you derive series for quantities such as \pi?


Look for functions that have pi as an argument or output that is easily found and get their taylor series.

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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 06:01:02 UTC 
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glebovg wrote:
Also, I do not think the Cauchy product would give me the explicit form for \pi e and \frac{\pi }{e}.


Why not?

For example,
\begin{aligned}
\pi&=\sum_{n\in\mathbb{N}} \frac{(n!)^2 2^{n+1}}{(2n+1)!}\\
e&=\sum_{n\in\mathbb{N}} \frac{1}{n!}\\
e^{-1}&=\sum_{n\in\mathbb{N}} \frac{(-1)^n}{n!}
\end{aligned}
are absolutely convergent series, so taking products,
\begin{aligned}
\pi e&=\sum_{(m,n)\in\mathbb{N}^2}\frac{(n!)^2 2^{n+1}}{(2n+1)!m!}\\
\frac{\pi}{e}&=\sum_{(m,n)\in\mathbb{N}^2}\frac{(-1)^m(n!)^2 2^{n+1}}{(2n+1)!m!}
\end{aligned}
are series representation of \pi e and \pi/e.

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\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 06:02:02 UTC 
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Shadow wrote:
glebovg wrote:
How do you generally come up with series representations, say for \pi?

I know Ramanujan came up with a lot of formulas for \pi and other quantities without any derivations, but how would you derive series for quantities such as \pi?


Look for functions that have pi as an argument or output that is easily found and get their taylor series.


I think Ramanujan was looking at hypergeometric functions or suchlikes.

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\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 06:04:07 UTC 
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Thanks for help.


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 Post subject: Re: Series
PostPosted: Mon, 9 Jul 2012 06:09:10 UTC 
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outermeasure wrote:
Shadow wrote:
glebovg wrote:
How do you generally come up with series representations, say for \pi?

I know Ramanujan came up with a lot of formulas for \pi and other quantities without any derivations, but how would you derive series for quantities such as \pi?


Look for functions that have pi as an argument or output that is easily found and get their taylor series.


I think Ramanujan was looking at hypergeometric functions or suchlikes.


Yes, he beat that horse to death a lot.

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