S.O.S. Mathematics CyberBoard

I have this equation: Tanx = V^2/gr or r = V^2/gtanx

How do I derive the equation of Rate of Turn using the above equation?

The equation result would be: ROT = gtan(x)/V(feet per second) The equation calculates ROT in Radians/sec.

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Without knowing what any of those variables are, who knows?

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r is radius in feet
g gravity 32.2m/s

V Feet/Sec

Tan(x) Tan of the Bank Angle

My best attempt is:

D=Vt

t = D/V and C = 2pi(r)

t = 2pi(r)/V and r=V^2/gtan(x)

Thus: t = 2pi[(V^2/gtan(x))]/V

And: t = 2(pi)V/gtan(x)

However, I think I may be missing some important steps. The ROT is not taken into account and I am not sure how to make an equation for ROT to insert into the main equation.

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Presumably your represents the equivalent linear velocity at radius where you have a purely rotational motion, in which case use to get .

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Ok, that was a lot easier. Did not think in that direction.

But, was I on the right track with my work, what did I need to do finish the work?

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