I am trying to find initial velocity to reach a certain height
So here's what i got
v^2 = 2g((R^2)/(R+h))-2gR+V(0)^2
v0^2 = 2gR - 2g((R^2)/(R+h)) + v^2
so v^2 is 0 cause at the velocity of h the rocket stops. and now solve for V0
v0 = √(2gR) - √(2g((R^2)/(R+h)))
R= 6378.1 km
h= 450 km
g= 9.80665 m/s2 = 127094.184 km/hr2
v0 = √((2)(127094.184)(6378.1)) - √(2(127094.184)((6378.1^2)/(6378.1+450)))
v0 = 1328.1287 km/hr = 368.9246 m/s
Did i solve this correctly?
when i try to do this in metres instead of kiometers using the variables
R= 6378100 m
h= 450000 m
g= 9.80665 m/s2
i get v0 = 374.7107 m/s
is this more or less accurate? are my units of measurement correct when i plug them in the equation?
does not mean
But then that might mean that
....what will we tell the freshmen?