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DgrayMan
 Post subject: Re: if (x^3)ax=a' then a has a cube root.
PostPosted: Tue, 31 Jan 2012 17:43:22 UTC 
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In x(a(x^2)ax)x(a(x^2)ax)=xexe , how do we know a(x^2)ax=e?
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 Post subject: Re: if (x^3)ax=a' then a has a cube root.
PostPosted: Tue, 31 Jan 2012 19:32:10 UTC 
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DgrayMan wrote:
In x(a(x^2)ax)x(a(x^2)ax)=xexe , how do we know a(x^2)ax=e?


Because x^2ax=a^{-1}, so multiply by a on the left on both sides.

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