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 Post subject: Augmented matrixPosted: Tue, 3 Mar 2009 19:15:59 UTC

Joined: Mon, 16 Feb 2009 06:30:28 UTC
Posts: 5
I tried so many times but I still could not get it...

3x + y = 2
4x â€“ 2y = -3

the ans is supposed to be (1/10,17/10))

much appreciated

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 Post subject: Posted: Tue, 3 Mar 2009 21:04:55 UTC
 Member of the 'S.O.S. Math' Hall of Fame

Joined: Mon, 23 Feb 2009 23:20:33 UTC
Posts: 1049
Multiply the first equation by 4, and multiply the second equation by 3. Then subtract one from the other.

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 Post subject: Posted: Wed, 4 Mar 2009 05:44:26 UTC

Joined: Mon, 16 Feb 2009 06:30:28 UTC
Posts: 5
augumentation goes like this

[3 1 | 2]
[4 -2 | -3]

i dunno how to implement the next step?

ans =1/10,17/10

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 Post subject: Posted: Wed, 4 Mar 2009 06:24:14 UTC
 Member of the 'S.O.S. Math' Hall of Fame

Joined: Tue, 20 Nov 2007 04:36:12 UTC
Posts: 826
Location: Las Cruces
Let the new second row be the old second row minus (4/3) times the first row.

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 Post subject: Posted: Wed, 4 Mar 2009 08:04:05 UTC

Joined: Mon, 16 Feb 2009 06:30:28 UTC
Posts: 5
i still dont get it!

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 Post subject: Posted: Wed, 4 Mar 2009 08:18:43 UTC

Joined: Thu, 15 Feb 2007 06:35:15 UTC
Posts: 755

We want to get it into reduced row echelon form, so the first step is to snag a 0 in the lower left corner using only elementary row operations (addition, scalar mulitplication, swap)

so, lets subtract 4/3 row 1 from row 2

okay so now its in row echelon form, lets get it to reduced row echelon form by getting a zero in the top right corner (not including the augmentation obv.)

in the end you can mulitply each row by a scalar in order to get

_________________

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 Post subject: Re: Augmented matrixPosted: Sat, 7 Mar 2009 19:28:40 UTC
 Member of the 'S.O.S. Math' Hall of Fame

Joined: Mon, 19 May 2003 19:55:19 UTC
Posts: 7949
Location: Lexington, MA
Hello, kabdul02!

Quote:

I'll do it head-on . . .

.

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