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jojo
 Post subject: integrals
PostPosted: Thu, 28 Aug 2008 18:31:37 UTC 
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integral 6e^3x dx
0

any idea i need to evaluate the integral, add the 1 and 0 in place of the x
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lepton
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PostPosted: Thu, 28 Aug 2008 18:57:47 UTC 
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\int_0^1 6e^{3x}dx=2e^{3x}\big{|}_0^1=2(e^3-e^0)=2e^3-2.
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