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 Post subject: Continuity Equation in Polar Coordinates (Fluids)
PostPosted: Mon, 23 Apr 2012 18:11:55 UTC 
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I have the continuity equation in the form div(u)=0. u=ui+vj. (Couldn't work out how to do vectors in latex)

In cartesian coordinates, this is:

\frac{\partial u}{\partial x} + \frac{\partial v}{\partial y} = 0

I need to be able to convert from this to polar coordinates, which should give:

\frac{1}{r}\frac{\partial}{\partial r}(ru_{r}) + \frac{1}{r}\frac{\partial u}{\partial\theta}\theta

I've tried using x=rcos\theta and y=rsin\theta, but I can't seem to get that result or figure out what I'm doing wrong. Most of the internet seems to use different notation to what I'm used to, which doesn't help either!

Thanks for any help.


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 Post subject: Re: Continuity Equation in Polar Coordinates (Fluids)
PostPosted: Mon, 23 Apr 2012 21:59:41 UTC 
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Joined: Wed, 21 May 2003 04:27:18 UTC
Posts: 992
apgraves1 wrote:
I have the continuity equation in the form div(u)=0. u=ui+vj. (Couldn't work out how to do vectors in latex)

In cartesian coordinates, this is:

\frac{\partial u}{\partial x} + \frac{\partial v}{\partial y} = 0

I need to be able to convert from this to polar coordinates, which should give:

\frac{1}{r}\frac{\partial}{\partial r}(ru_{r}) + \frac{1}{r}\frac{\partial u}{\partial\theta}\theta

I've tried using x=rcos\theta and y=rsin\theta, but I can't seem to get that result or figure out what I'm doing wrong. Most of the internet seems to use different notation to what I'm used to, which doesn't help either!

Thanks for any help.


Google yielded this.

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"Mathematicians are like lovers. Grant a mathematician the least principle, and he will draw from it a consequence which you must also grant him, and from this consequence another." Bernard Le Bovier Fontenelle (1657-1757)

"In great mathematics there is a very high degree of unexpectedness, combined with inevitability and economy."
G.H. Hardy (1877-1947)


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