What is the molality of a 10.5% by mass glucose (C6H12O6) sol'n? The density of the sol'n is 1.03g/mL
Molality (I call it "Mal") = mol solute/kg solvent
My biggest issue for this question is with getting rid of the 'mL'. I don't know of any other conversion factor to get rid of it. In fact, from the "by mass" part, I got:
10.5 g C6H12O6
100 g soln
So I I multiply this by:
1.03 g soln
1 mL soln
I get rid of the "g soln" term, but I don't know how to get rid of the "mL soln" term..
You should know that there is
particles, which means if you know the density of a particle...