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 Post subject: Distribution questions
PostPosted: Wed, 15 Jul 2009 16:26:48 UTC 
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Joined: Wed, 29 Dec 2004 21:23:09 UTC
Posts: 120
Hi, have two questions

I wanna calculate f\delta' where f is a function of x and
\delta is the dirac function. \varphi is a testfunction


f\delta' = \ <f\delta',\varphi> \ = \  <\delta',f\varphi> \ = \ -<\delta,(f\varphi)'> \ = \   \int_{-\infty}^{\infty} \delta(x)(f(x)\varphi(x))',dx \\

Im not really sure how to proceed from here, should I use partial integration? Ive tried it but not sure.

Next question

I want to derivate f(x) = abs(x) as a distribution

<f',\varphi> \ = \ -<f,\varphi'> \ = \  -\int_{-\infty}^{\infty} f(x)\varphi(x)',dx  \ = \ (Partial int.) \ = \ \int_{-\infty}^{\infty} f(x)'\varphi(x),dx

Then I simply put in the values of f(x) and I get

\int_{0}^{\infty}\varphi(x),dx - \int_{-\infty}^{0}\varphi(x),dx \ = \ 2H where H is the heavieside function

But the answer says 2H - 1


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 Post subject:
PostPosted: Wed, 15 Jul 2009 17:01:01 UTC 
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Senior Member

Joined: Wed, 29 Dec 2004 21:23:09 UTC
Posts: 120
Question 1 solved


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 Post subject: Re: Distribution questions
PostPosted: Mon, 24 Aug 2009 16:56:44 UTC 
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S.O.S. Newbie

Joined: Mon, 24 Aug 2009 11:40:23 UTC
Posts: 3
ej wrote:
Hi, have two questions

I wanna calculate f\delta' where f is a function of x and
\delta is the dirac function. \varphi is a testfunction


f\delta' = \ <f\delta',\varphi> \ = \  <\delta',f\varphi> \ = \ -<\delta,(f\varphi)'> \ = \   \int_{-\infty}^{\infty} \delta(x)(f(x)\varphi(x))',dx \\

Im not really sure how to proceed from here, should I use partial integration? Ive tried it but not sure.

Next question

I want to derivate f(x) = abs(x) as a distribution

<f',\varphi> \ = \ -<f,\varphi'> \ = \  -\int_{-\infty}^{\infty} f(x)\varphi(x)',dx  \ = \ (Partial int.) \ = \ \int_{-\infty}^{\infty} f(x)'\varphi(x),dx

Then I simply put in the values of f(x) and I get

\int_{0}^{\infty}\varphi(x),dx - \int_{-\infty}^{0}\varphi(x),dx \ = \ 2H where H is the heavieside function

But the answer says 2H - 1


for the second part.

see carefully what is the value of - \int_{-\infty}^{0}\varphi(x),dx .. this integral is same as \int_{-\infty}^{+\infty}(H-1).\varphi(x),dx and not \int_{-\infty}^{+\infty}H.\varphi(x),dx as you are claiming. in fact you have done all the work ... just you have to look carefully.


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