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 Post subject: Linear Algebra math problem, need help
PostPosted: Mon, 11 Oct 2010 03:58:57 UTC 
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Hey i have this math assignment due and i am really stuck. here it is:
Let A be a 3x2 matrix and B be a 2x3 matrix.

If AB is a 3x3 matrix =
8 2 -2
2 5 4
-2 4 5

Show that BA is a 2x2 matrix =
9 0
0 9

Any help would be appreciated!!
Thanks,


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 Post subject: Re: Linear Algebra math problem, need help
PostPosted: Mon, 11 Oct 2010 16:36:28 UTC 
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nsk11 wrote:
Hey i have this math assignment due and i am really stuck. here it is:
Let A be a 3x2 matrix and B be a 2x3 matrix.

If AB is a 3x3 matrix =
8 2 -2
2 5 4
-2 4 5

Show that BA is a 2x2 matrix =
9 0
0 9

Any help would be appreciated!!
Thanks,


The matrix AB is not invertible, so this limits what you can do with it....were you not given any more information??

_________________
"Mathematicians are like lovers. Grant a mathematician the least principle, and he will draw from it a consequence which you must also grant him, and from this consequence another." Bernard Le Bovier Fontenelle (1657-1757)

"In great mathematics there is a very high degree of unexpectedness, combined with inevitability and economy."
G.H. Hardy (1877-1947)


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 Post subject: no other information
PostPosted: Mon, 11 Oct 2010 16:58:38 UTC 
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Posts: 4
Location: Montreal
no my teacher said this is all i need

my attempt:

Brute force, using a system of 13 equations should not be the way to solve this question. This is more of a proof like problem.

Two things noted:
(1) AB is symmetric -- this should have something to do with the problem.
(2) Trace BA = Trace AB = 18 ( trace = sum of diagonals -- must be equal)

Also, by adding a row or column of zeros you can get 3 x 3 matrices, somewhat easier to work with. All determinants are zero so you can't invert them however.


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 Post subject: Re: Linear Algebra math problem, need help
PostPosted: Mon, 11 Oct 2010 17:00:54 UTC 
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nsk11 wrote:
Hey i have this math assignment due and i am really stuck. here it is:
Let A be a 3x2 matrix and B be a 2x3 matrix.

If AB is a 3x3 matrix =
8 2 -2
2 5 4
-2 4 5

Show that BA is a 2x2 matrix =
9 0
0 9

Any help would be appreciated!!
Thanks,


Hint: Changing A to P^{-1}A and B to BP at the same time has the effect of changing AB to P^{-1}(AB)P and leaving BA unchanged. Similarly, changing A to AQ and B to Q^{-1}B has the effect ....

_________________
\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


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 Post subject:
PostPosted: Mon, 11 Oct 2010 17:37:01 UTC 
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Location: Montreal
Changing A to P^-1 * A and B to BP at the same time has the effect of changing AB to (P^-1)(AB)P and leaving BA unchanged. Similarly, changing A to AQ and B to (Q^-1)B has the effect (Q^-1)(BA)Q and leaving AB unchanged.

I understand that, where should i go from there?


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 Post subject:
PostPosted: Mon, 11 Oct 2010 18:13:06 UTC 
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nsk11 wrote:
Changing A to P^-1 * A and B to BP at the same time has the effect of changing AB to (P^-1)(AB)P and leaving BA unchanged. Similarly, changing A to AQ and B to (Q^-1)B has the effect (Q^-1)(BA)Q and leaving AB unchanged.

I understand that, where should i go from there?


Maybe that wasn't that great a hint. It is a simplifying step if you want to brute-force your way.

For a more elegant solution --- Do you know how the minimal polynomials of ST and TS, where S, T are linear maps S\colon V_1\to V_2 and T\colon V_2\to V_1, relate to each other?

_________________
\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


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 Post subject:
PostPosted: Mon, 11 Oct 2010 18:40:40 UTC 
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Joined: Mon, 11 Oct 2010 03:57:06 UTC
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Location: Montreal
No not really, i know what a linear map is, but i don't see how it is applicable to this problem


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