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 Post subject: Banded Matrix
PostPosted: Tue, 28 Sep 2010 22:23:20 UTC 
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Hi there,

On page 12 of the following document:

http://www.finmod.co.za/Hagan_West_curves_AMF.pdf

It shows a banded matrix it also says that the first line sets c = 0 and the last line is

b_{n-1}+ 2_{c-1}h_{n-1}+ 3_{d-1}h^2_{n-1}

I've looked up what I can on banded matrices and I understand how such matrices can be expressed in a more compact reduced form. But I am still not clear how the matrices shown on page 12 should be multiplied out to give the results stated above?

It can't be straightforward matrix multiplication as the number of columns in matrix A are not equal to the number of rows in x?

Thanks

Baz


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 Post subject: Re: Banded Matrix
PostPosted: Wed, 29 Sep 2010 04:47:20 UTC 
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Bazman wrote:
Hi there,

On page 12 of the following document:

http://www.finmod.co.za/Hagan_West_curves_AMF.pdf

It shows a banded matrix it also says that the first line sets c = 0 and the last line is

b_{n-1}+ 2_{c-1}h_{n-1}+ 3_{d-1}h^2_{n-1}

I've looked up what I can on banded matrices and I understand how such matrices can be expressed in a more compact reduced form. But I am still not clear how the matrices shown on page 12 should be multiplied out to give the results stated above?

It can't be straightforward matrix multiplication as the number of columns in matrix A are not equal to the number of rows in x?

Thanks

Baz


It is straightforward matrix multiplication, as long as you remember what actually your more compact form represents. Remember \times denotes the "wasted" space, and you read each column of the compact form as (sub/./super) diagonal (according to where and how many \times appears in the column) of a banded matrix. Convert it back to banded matrix and multiply.

_________________
\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


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 Post subject:
PostPosted: Wed, 29 Sep 2010 10:39:42 UTC 
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So the banded matrix formulation is simply to make displaying and storing the martix easier.

But to carry out any calculations you have to convert it back to its earlier form?

Baz


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 Post subject:
PostPosted: Wed, 29 Sep 2010 12:45:35 UTC 
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Bazman wrote:
So the banded matrix formulation is simply to make displaying and storing the martix easier.

But to carry out any calculations you have to convert it back to its earlier form?

Baz


Well you can avoid converting them back, e.g. using LAPACK's routine DGBSV or similar.

_________________
\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


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 Post subject:
PostPosted: Thu, 30 Sep 2010 00:32:05 UTC 
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thanks OM!!


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