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blalaw1987
 Post subject: Solving for Undetermined Coefficents - Particular Solution
PostPosted: Wed, 15 Feb 2012 07:24:56 UTC 
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I am solving for the general solution of non-homogeous DE. I have the complementary part of the general solution just having trouble with the particular solution part on this one.

I have

2y'' 3y' - 2y = 6x^2e^x - 4x^2 + 12

y = Ax^2e^x + bx^2 or would it be
y = Ax^2e^x + (bx^2 +cx+d) and the differienate to find y' and y'' and plug it back in am I doing this one write or is it the second method?
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helmut
 Post subject: Re: Solving for Undetermied Coefficents - Particular Solutio
PostPosted: Wed, 15 Feb 2012 07:47:33 UTC 
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It's worse:
y = (Ax^2 + Bx+C)e^x+(Dx^2 +Ex+F)

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blalaw1987
 Post subject: Re: Solving for Undetermined Coefficents - Particular Soluti
PostPosted: Wed, 15 Feb 2012 07:52:51 UTC 
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ok thaks I was sure with the x^2 as well i the first product as well.
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