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 Post subject: f is boundedPosted: Mon, 6 Feb 2012 06:27:40 UTC
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Joined: Mon, 6 Feb 2012 06:18:16 UTC
Posts: 25
Consider the set and a function so that for each is and for all is Prove that for all is

I don't think if I can solve this, since the condition is false if I take Could this problem be solved? Or do we have to change it?

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 Post subject: Re: f is boundedPosted: Mon, 6 Feb 2012 06:32:56 UTC
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Joined: Mon, 29 Dec 2008 17:49:32 UTC
Posts: 6071
Location: 127.0.0.1, ::1 (avatar courtesy of UDN)
LegendZKiller wrote:
Consider the set and a function so that for each is and for all is Prove that for all is

I don't think if I can solve this, since the condition is false if I take Could this problem be solved? Or do we have to change it?

What is H(S)?

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 Post subject: Re: f is boundedPosted: Mon, 6 Feb 2012 13:18:48 UTC
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Joined: Mon, 6 Feb 2012 06:18:16 UTC
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Holomorphic function.

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 Post subject: Re: f is boundedPosted: Mon, 6 Feb 2012 14:47:42 UTC
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It doesn't work for --- so what? Obviously you don't want since it is unbounded in S (consider the positive real axis).

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 Post subject: Re: f is boundedPosted: Tue, 7 Feb 2012 02:38:48 UTC
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Joined: Mon, 6 Feb 2012 06:18:16 UTC
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Yes well so it can't be solved right? I mean, how could we formule the problem in order to solve it?

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 Post subject: Re: f is boundedPosted: Tue, 7 Feb 2012 02:39:58 UTC
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Joined: Wed, 30 Mar 2005 04:25:14 UTC
Posts: 12172
Location: Austin, TX
LegendZKiller wrote:
Yes well so it can't be solved right? I mean, how could we formule the problem in order to solve it?

What do you mean? What is your actual goal to understand?

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