S.O.S. Mathematics CyberBoard

Your Resource for mathematics help on the web!
It is currently Wed, 19 Jun 2013 22:45:20 UTC

All times are UTC [ DST ]




Post new topic Reply to topic  [ 7 posts ] 
Author Message
 Post subject: Modulus and complex variable
PostPosted: Mon, 6 Feb 2012 06:24:33 UTC 
Offline
Member

Joined: Mon, 6 Feb 2012 06:18:16 UTC
Posts: 25
Let $f:B(0,2)\to B(0,2)$ be an analytic function so that $f(1)=0.$ Prove that for all $z\in B(0,2)$ is $\left| \dfrac{f(z)}{z} \right|\le \left| \dfrac{2(z-1)}{4-z} \right|.$

No clue on this one, any ideas? I thought on considering g(z)=(z-1)f(z) or perhaps g(z)=zf(z) but I don't see the trick to solve the problem.


Top
 Profile  
 
 Post subject: Re: Modulus and complex variable
PostPosted: Mon, 6 Feb 2012 06:29:39 UTC 
Offline
Moderator
User avatar

Joined: Mon, 29 Dec 2008 17:49:32 UTC
Posts: 6068
Location: 127.0.0.1, ::1 (avatar courtesy of UDN)
LegendZKiller wrote:
Let $f:B(0,2)\to B(0,2)$ be an analytic function so that $f(1)=0.$ Prove that for all $z\in B(0,2)$ is $\left| \dfrac{f(z)}{z} \right|\le \left| \dfrac{2(z-1)}{4-z} \right|.$

No clue on this one, any ideas? I thought on considering g(z)=(z-1)f(z) or perhaps g(z)=zf(z) but I don't see the trick to solve the problem.


Schwarz-Pick.

_________________
\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


Top
 Profile  
 
 Post subject: Re: Modulus and complex variable
PostPosted: Mon, 6 Feb 2012 13:19:36 UTC 
Offline
Member

Joined: Mon, 6 Feb 2012 06:18:16 UTC
Posts: 25
I don't get how to apply it, can you show me please?


Top
 Profile  
 
 Post subject: Re: Modulus and complex variable
PostPosted: Mon, 6 Feb 2012 14:50:33 UTC 
Online
Moderator
User avatar

Joined: Wed, 30 Mar 2005 04:25:14 UTC
Posts: 12172
Location: Austin, TX
LegendZKiller wrote:
I don't get how to apply it, can you show me please?


Huh? You know the center and radius of the ball you're working on, where's the problem?

_________________
(\ /)
(O.o)
(> <)
This is Bunny. Copy Bunny into your signature to help him on his way to world domination


Top
 Profile  
 
 Post subject: Re: Modulus and complex variable
PostPosted: Tue, 7 Feb 2012 02:37:49 UTC 
Offline
Member

Joined: Mon, 6 Feb 2012 06:18:16 UTC
Posts: 25
I don't see the trick, I suppose to take a function, for example f(z)=(z-1)h(z), something like that, and having the ball I have that |z|<2 right?


Top
 Profile  
 
 Post subject: Re: Modulus and complex variable
PostPosted: Tue, 7 Feb 2012 02:39:16 UTC 
Online
Moderator
User avatar

Joined: Wed, 30 Mar 2005 04:25:14 UTC
Posts: 12172
Location: Austin, TX
LegendZKiller wrote:
I don't see the trick, I suppose to take a function, for example f(z)=(z-1)h(z), something like that, and having the ball I have that |z|<2 right?


What? Do you know the Schwarz-Pick theorem?

_________________
(\ /)
(O.o)
(> <)
This is Bunny. Copy Bunny into your signature to help him on his way to world domination


Top
 Profile  
 
 Post subject: Re: Modulus and complex variable
PostPosted: Tue, 7 Feb 2012 03:12:12 UTC 
Offline
Moderator
User avatar

Joined: Mon, 29 Dec 2008 17:49:32 UTC
Posts: 6068
Location: 127.0.0.1, ::1 (avatar courtesy of UDN)
Oops...

Are you sure the denominator of LHS of the desired inequality is z not 2? For that you need to assume f(0)=0 in addition (which also has the effect of replacing the \leq with < except at z=1).

_________________
\begin{aligned}
Spin(1)&=O(1)=\mathbb{Z}/2&\quad&\text{and}\\
Spin(2)&=U(1)=SO(2)&&\text{are obvious}\\
Spin(3)&=Sp(1)=SU(2)&&\text{by }q\mapsto(\mathop{\mathrm{Im}}\mathbb{H}\ni p\mapsto qp\bar{q})\\
Spin(4)&=Sp(1)\times Sp(1)&&\text{by }(q_1,q_2)\mapsto(\mathbb{H}\ni p\mapsto q_1p\bar{q_2})\\
Spin(5)&=Sp(2)&&\text{by }\mathbb{HP}^1\cong S^4_{round}\hookrightarrow\mathbb{R}^5\\
Spin(6)&=SU(4)&&\text{by the irrep }\Lambda_+\mathbb{C}^4
\end{aligned}


Top
 Profile  
 
Display posts from previous:  Sort by  
Post new topic Reply to topic  [ 7 posts ] 

All times are UTC [ DST ]


Who is online

Users browsing this forum: No registered users


You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum

Search for:
Jump to:  
Contact Us | S.O.S. Mathematics Homepage
Privacy Statement | Search the "old" CyberBoard

users online during the last hour
Powered by phpBB © 2001, 2005-2011 phpBB Group.
Copyright © 1999-2013 MathMedics, LLC. All rights reserved.
Math Medics, LLC. - P.O. Box 12395 - El Paso TX 79913 - USA