S.O.S. Mathematics CyberBoard

Your Resource for mathematics help on the web!
It is currently Sun, 19 May 2013 01:54:43 UTC

All times are UTC [ DST ]




Post new topic Reply to topic  [ 4 posts ] 
Author Message
 Post subject: Hyperbola
PostPosted: Fri, 23 May 2003 10:26:27 UTC 
Given hyperbola x^2-y^2=1

Find the point on the Oy-axis from which the tangent lines to the hyperbola are perpendicular


Top
  
 
 Post subject:
PostPosted: Fri, 23 May 2003 11:57:58 UTC 
Offline
S.O.S. Oldtimer

Joined: Mon, 19 May 2003 07:15:29 UTC
Posts: 204
Location: Los Angeles
I'm not quite sure which tangent lines you're asking about ..

Here is a graph of your function:
Image

Could you illustrate where the tangent lines might be, and where the location of the point you're interested in would be?
Just give a rough idea, then we'll figure out exactly where it should go.

_________________
My thoughts on Pi:
How I need a drink, alcoholic of course, drunk for happy feelings ...


Top
 Profile  
 
 Post subject:
PostPosted: Fri, 23 May 2003 12:32:08 UTC 
It is asked for the point on Oy-axis where the tangent lines to hyperbola are perpendicular...So the tangent lines depend on the point on the Oy-axis practically.Let me state an example:

1 line could be tangent in (-1,-1/2),the other in (1,1/2) and they're perpendicular in (0,1)

This is just an example to illustrate what i want,and is probably not true.

Also there is the possibility that such a point where the tangent lines are perpendicular,doesnt exist.But i have to bring a proof up for this...


Top
  
 
 Post subject:
PostPosted: Fri, 23 May 2003 19:42:52 UTC 
Offline
S.O.S. Oldtimer

Joined: Tue, 20 May 2003 17:25:56 UTC
Posts: 235
Location: Israel
hi, try this:
let A(p;t) be one of the points on the Oy-axis from which the tangent lines to the hyperbola are perpendicular. try to express p by t or the opposite. if it'll go ok you will get some function and the "points on the Oy-axis from which the tangent lines to the hyperbola are perpendicular" will be located on it. then you can swich p and t to x and y if you want.
hope it helps. :roll:
Good Luck :wink:


Top
 Profile  
 
Display posts from previous:  Sort by  
Post new topic Reply to topic  [ 4 posts ] 

All times are UTC [ DST ]


Who is online

Users browsing this forum: No registered users


You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum

Search for:
Jump to:  
Contact Us | S.O.S. Mathematics Homepage
Privacy Statement | Search the "old" CyberBoard

users online during the last hour
Powered by phpBB © 2001, 2005-2011 phpBB Group.
Copyright © 1999-2013 MathMedics, LLC. All rights reserved.
Math Medics, LLC. - P.O. Box 12395 - El Paso TX 79913 - USA