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 Post subject: Trig Function Application QuestionPosted: Wed, 18 Jul 2012 00:52:36 UTC
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Joined: Tue, 17 Jul 2012 23:48:33 UTC
Posts: 1
Hey, I'm having difficulty with this question.

A Ferris wheel has a radius of 10m and makes one revolution every 12 s. Draw a graph and find an equation to show a person's height above or below the centre of rotation for two counterclockwise revolutions starting at the
highest point of the ferris wheel. ( there were two other points that I have to graph, but if I get this one, I'll hopefully understand the rest)

There was also a picture. It showed a circle ( basically the ferris wheel), and it's divided into 12 "pieces" or parts. Each "piece" is 30 degrees. I was wondering, what would the x and y axis be then? I tried to graph it, and labelled the x-axis as the seconds, and the y-axis as the height in metres. But then...how am I suppose to incorporate the 30 degrees in this??

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 Post subject: Re: Trig Function Application QuestionPosted: Wed, 18 Jul 2012 02:06:27 UTC
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Joined: Sun, 24 Jul 2005 20:12:39 UTC
Posts: 3692
Location: Ottawa Ontario
What do you know about a right triangle with an angle = 30 degrees?

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 Post subject: Re: Trig Function Application QuestionPosted: Wed, 18 Jul 2012 04:55:07 UTC
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Joined: Wed, 30 Mar 2005 04:25:14 UTC
Posts: 12103
Location: Austin, TX
bobbitins wrote:
Hey, I'm having difficulty with this question.

A Ferris wheel has a radius of 10m and makes one revolution every 12 s. Draw a graph and find an equation to show a person's height above or below the centre of rotation for two counterclockwise revolutions starting at the
highest point of the ferris wheel. ( there were two other points that I have to graph, but if I get this one, I'll hopefully understand the rest)

There was also a picture. It showed a circle ( basically the ferris wheel), and it's divided into 12 "pieces" or parts. Each "piece" is 30 degrees. I was wondering, what would the x and y axis be then? I tried to graph it, and labelled the x-axis as the seconds, and the y-axis as the height in metres. But then...how am I suppose to incorporate the 30 degrees in this??

Have you drawn a picture and labeled things like direction of rotation? It helps a lot in terms of setting things up and lowering a student's confusion level to one manageable enough to deal with using what they already know.

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