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 Post subject: mathmatical operationPosted: Wed, 19 Dec 2007 20:29:17 UTC

Joined: Mon, 24 Apr 2006 21:50:36 UTC
Posts: 5
{x(a-2x)}{2bsqrt(a-x)x}+{sqrt(a-x)x}{b}={x(3a-4x)}{2bsqrt(a-x)x I do not understand how the numerator of the answer is derived. Thank you.

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 Post subject: Posted: Wed, 19 Dec 2007 21:09:32 UTC
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Joined: Tue, 20 Nov 2007 04:36:12 UTC
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Are you asking how to write this formula in Latex? Or did you mean to put this question in the Algebra section instead of this section?

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 Post subject: Posted: Wed, 19 Dec 2007 23:01:13 UTC

Joined: Mon, 24 Apr 2006 21:50:36 UTC
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You're right both times. I am trying to teach myself math. Do I factor the first numerator?

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 Post subject: Re: mathmatical operationPosted: Thu, 20 Dec 2007 00:33:44 UTC
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sch wrote:
{x(a-2x)}{2bsqrt(a-x)x}+{sqrt(a-x)x}{b}={x(3a-4x)}{2bsqrt(a-x)x I do not understand how the numerator of the answer is derived. Thank you.

is this what you are looking for...

Code:
$$\frac{x(a-2x)}{2b\sqrt{a-x}x}+\frac{\sqrt{a-x}x}{b}=\frac{x(3a-4x)}{2b\sqrt{a-x}x}$$

or this...

Code:
$$\frac{x(a-2x)}{2b\sqrt{(a-x)x}}+\frac{\sqrt{(a-x)x}}{b}=\frac{x(3a-4x)}{2b\sqrt{(a-x)x}}$$

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 Post subject: Posted: Thu, 20 Dec 2007 00:42:49 UTC

Joined: Mon, 24 Apr 2006 21:50:36 UTC
Posts: 5
the second

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 Post subject: Re: mathmatical operationPosted: Thu, 20 Dec 2007 02:49:00 UTC
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Location: New Junk City

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