mathmatical operation

sch · **Joined:** Mon, 24 Apr 2006 21:50:36 UTC **Posts:** 5

{x(a-2x)}{2bsqrt(a-x)x}+{sqrt(a-x)x}{b}={x(3a-4x)}{2bsqrt(a-x)x I do not understand how the numerator of the answer is derived. Thank you.

tashirosgt · **Posted:** Wed, 19 Dec 2007 21:09:32 UTC

Are you asking how to write this formula in Latex? Or did you mean to put this question in the Algebra section instead of this section?

sch · **Joined:** Mon, 24 Apr 2006 21:50:36 UTC **Posts:** 5

You're right both times. I am trying to teach myself math. Do I factor the first numerator?

Zone Ranger · **Posted:** Thu, 20 Dec 2007 00:33:44 UTC

sch wrote:

{x(a-2x)}{2bsqrt(a-x)x}+{sqrt(a-x)x}{b}={x(3a-4x)}{2bsqrt(a-x)x I do not understand how the numerator of the answer is derived. Thank you.

is this what you are looking for...

$$\frac{x(a-2x)}{2b\sqrt{a-x}x}+\frac{\sqrt{a-x}x}{b}=\frac{x(3a-4x)}{2b\sqrt{a-x}x}$

Code:

[tex]$\frac{x(a-2x)}{2b\sqrt{a-x}x}+\frac{\sqrt{a-x}x}{b}=\frac{x(3a-4x)}{2b\sqrt{a-x}x}[/tex]

or this...

$$\frac{x(a-2x)}{2b\sqrt{(a-x)x}}+\frac{\sqrt{(a-x)x}}{b}=\frac{x(3a-4x)}{2b\sqrt{(a-x)x}}$

Code:

[tex]$\frac{x(a-2x)}{2b\sqrt{(a-x)x}}+\frac{\sqrt{(a-x)x}}{b}=\frac{x(3a-4x)}{2b\sqrt{(a-x)x}}[/tex]

sch · **Joined:** Mon, 24 Apr 2006 21:50:36 UTC **Posts:** 5

the second

Zone Ranger · **Posted:** Thu, 20 Dec 2007 02:49:00 UTC

$$\frac{x(a-2x)}{2b\sqrt{(a-x)x}}+\frac{\sqrt{(a-x)x}}{b}$
$$=\frac{x(a-2x)}{2b\sqrt{(a-x)x}}+\frac{2\sqrt{(a-x)x}\sqrt{(a-x)x}}{2b\sqrt{(a-x)x}}$
$$=\frac{x(a-2x)+2(a-x)x}{2b\sqrt{(a-x)x}}$
$$=\frac{x(a-2x+2(a-x))}{2b\sqrt{(a-x)x}}$
$$=\frac{x(a-2x+2a-2x))}{2b\sqrt{(a-x)x}}$
$$=\frac{x(3a-4x)}{2b\sqrt{(a-x)x}}$

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mathmatical operation

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