S.O.S. Mathematics CyberBoard

I have so much difficulties understanding call and put options concept properly.





Let C be the price of a call option to purchase a stock whose present price is S. Suppose that interest is compounded continuously at nominal rate r. Show that if



C>S, then buying one stock and selling one call gives an arbitrage opportunity. What relationship do you conclude must exist between S and C if there is to be no arbitrage opportunity?



Solution: Suppose C>S. Buying a stock and selling a call will give you C-S>0. ( I know call option is the right(but not the obligation to purchase stock at expiration time t for strike price K but what do they mean by selling a call? what do you really sell? how does it change if you sell 10 calls or buy a 5 puts etc?). Put C-S>0 in the bank at time t you will have in the bank and a stock.



Thanks for any help.

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