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 Post subject: Algebra 2 PLEASE HELP!!!!Posted: Mon, 23 Apr 2012 17:57:57 UTC
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Joined: Mon, 23 Apr 2012 17:24:58 UTC
Posts: 36
Solve each system by the addition method.

-2x + 3y = -7
3x + y = 16

Put your answer in ordered pair (x, y) form.

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 Post subject: Re: Algebra 2 PLEASE HELP!!!!Posted: Mon, 23 Apr 2012 18:09:14 UTC
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Joined: Wed, 30 Mar 2005 04:25:14 UTC
Posts: 12172
Location: Austin, TX
Lil Kush wrote:
Solve each system by the addition method.

-2x + 3y = -7
3x + y = 16

Put your answer in ordered pair (x, y) form.

What have you tried? Are you familiar with examples you've seen in class where your teacher has used the addition method?

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 Post subject: Re: Algebra 2 PLEASE HELP!!!!Posted: Mon, 23 Apr 2012 18:16:38 UTC
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Joined: Mon, 23 Apr 2012 17:24:58 UTC
Posts: 36
I'm taking this online so I have no help. I did however ask one of the math teachers if the could help. He showed me how to plug it in the calculator but when i took my test and used his advice it failed me.

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 Post subject: Re: Algebra 2 PLEASE HELP!!!!Posted: Tue, 24 Apr 2012 05:35:58 UTC
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Joined: Mon, 19 May 2003 19:55:19 UTC
Posts: 7961
Location: Lexington, MA
Hello, Lil Kush!

You should have been shown the procedure before assigning this problem.

Quote:
Solve by the addition method: .

With the "addition method", we hope to ADD the two equations and have one of the variables drop out.
. . Then we can solve for the remaining variable . . . and we're on our way!

If we add the equation now, we get: .
. . We still have both an and a . . . that didn't work.

But here is something we can do . . .
. . We can multiply an equation by any number (except zero).

We can match the -terms "match up" if we multiply equation [2] by -3.

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